MHT CET · Physics · Alternating Current
In an a. c. circuit the instantaneous current and e.m.f. are represented as \(i=i_o \sin \left(\omega t-\frac{\pi}{6}\right)\) and \(E=E_o \sin \left(\omega t+\frac{\pi}{3}\right)\) respectively. The voltage leads the current by
- A \(\frac{\pi}{2}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
The phase of the current \(=-\frac{\pi}{6}\)
The phase of voltage \(=+\frac{\pi}{3}\)
Hence the voltage leads current by phase angle
\(\phi=\left(\frac{\pi}{6}\right)-\left(-\frac{\pi}{3}\right)=\frac{\pi}{2}\)
The phase of voltage \(=+\frac{\pi}{3}\)
Hence the voltage leads current by phase angle
\(\phi=\left(\frac{\pi}{6}\right)-\left(-\frac{\pi}{3}\right)=\frac{\pi}{2}\)
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