MHT CET · Physics · Wave Optics
In a Young's double slit experiment wavelength of light used is \(6000 Å\). The first order maxima and tenth order maxima fall at 14.50 mm and 16.75 mm from the particular reference point in the interference pattern respectively. If the wavelength is changed to \(5500 Å\) then the position of zero order and tenth order maxima are respectively [The other arrangements remaining same]
- A \(14.25 \mathrm{~mm}, 16.55 \mathrm{~mm}\)
- B \(12.25 \mathrm{~mm}, 14.55 \mathrm{~mm}\)
- C \(10.25 \mathrm{~mm}, 12.55 \mathrm{~mm}\)
- D \(16.25 \mathrm{~mm}, 18.55 \mathrm{~mm}\)
Answer & Solution
Correct Answer
(A) \(14.25 \mathrm{~mm}, 16.55 \mathrm{~mm}\)
Step-by-step Solution
Detailed explanation
\(Y_n = Y_0 + n \frac{\lambda D}{d}\) \(14.50 = Y_0 + 1 \cdot \frac{6000 D}{d}\)
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