MHT CET · Physics · Wave Optics
In a Young's double slit experiment, the fringe width is found to be \(2 \mathrm{~mm}\), when light of wavelength \(6000 Å\) is used. Find the change in fringe width if the whole apparatus is immersed in water of refractive index \(1.33 .\)
- A \(0.5 \mathrm{~mm}\)
- B \(1 \mathrm{~mm}\)
- C \(1.5 \mathrm{~mm}\)
- D \(2 \mathrm{~mm}\)
Answer & Solution
Correct Answer
(C) \(1.5 \mathrm{~mm}\)
Step-by-step Solution
Detailed explanation
Fringe width \(\beta=2 \mathrm{~mm}=2 \times 10^{-3} \mathrm{~m}\)
\(
\begin{aligned}
\lambda &=6000 Å \\
\mu &=1.33 \\
\beta^{\prime} &=? \\
\beta^{\prime} &=\frac{\beta}{\mu} \\
&=\frac{2}{1.33}=1.5 \mathrm{~mm}
\end{aligned}
\)
\(
\begin{aligned}
\lambda &=6000 Å \\
\mu &=1.33 \\
\beta^{\prime} &=? \\
\beta^{\prime} &=\frac{\beta}{\mu} \\
&=\frac{2}{1.33}=1.5 \mathrm{~mm}
\end{aligned}
\)
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