MHT CET · Physics · Thermodynamics
In a thermodynamic system, \(\Delta U\) represents the increases in its internal energy and \(\mathrm{dW}\) is the work done by the system then correct statement out of the following is
- A \(\Delta \mathrm{U}=\mathrm{dW}\) is an isothermal process
- B \(\Delta \mathrm{U}=-\mathrm{dW}\) is an adiabatic process
- C \(\Delta \mathrm{U}=-\mathrm{dW}\) is an isothermal process
- D \(\Delta \mathrm{U}=\mathrm{dW}\) is an adiabatic process
Answer & Solution
Correct Answer
(B) \(\Delta \mathrm{U}=-\mathrm{dW}\) is an adiabatic process
Step-by-step Solution
Detailed explanation
For an isothermal process, \(\Delta \mathrm{U}=0\).
According to first law of thermodynamics, \(\Delta \mathrm{Q}=\Delta \mathrm{U}+\mathrm{dW}\)
For an adiabatic process,
\(\Delta Q=0\)
\(\therefore \Delta \mathrm{U}=-\mathrm{dW}\)
\(\therefore\) It is an adiabatic process.
According to first law of thermodynamics, \(\Delta \mathrm{Q}=\Delta \mathrm{U}+\mathrm{dW}\)
For an adiabatic process,
\(\Delta Q=0\)
\(\therefore \Delta \mathrm{U}=-\mathrm{dW}\)
\(\therefore\) It is an adiabatic process.
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