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MHT CET · Physics · Wave Optics

In a single slit diffraction experiment, slit of width ' \(a\) ' is illuminated by light of wavelength ' \(\lambda\) ' and the width of the central maxima in diffraction pattern is measured as ' \(y\) '. When half of the slit is covered and illuminated by light of wavelength \((1 \cdot 5) \lambda\), the width of the central maximum in diffraction pattern becomes

  1. A \(\frac{3}{2} \mathrm{y}\)
  2. B \(\frac{2}{3} \mathrm{y}\)
  3. C 3 y
  4. D \(\frac{y}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(C) 3 y

Step-by-step Solution

Detailed explanation

Initial width of central maxima: \(y = \frac{2D\lambda}{a}\) New slit width: \(a' = \frac{a}{2}\)
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