MHT CET · Physics · Wave Optics
In a single slit diffraction experiment, slit of width ' \(a\) ' is illuminated by light of wavelength ' \(\lambda\) ' and the width of the central maxima in diffraction pattern is measured as ' \(y\) '. When half of the slit is covered and illuminated by light of wavelength \((1 \cdot 5) \lambda\), the width of the central maximum in diffraction pattern becomes
- A \(\frac{3}{2} \mathrm{y}\)
- B \(\frac{2}{3} \mathrm{y}\)
- C 3 y
- D \(\frac{y}{3}\)
Answer & Solution
Correct Answer
(C) 3 y
Step-by-step Solution
Detailed explanation
Initial width of central maxima: \(y = \frac{2D\lambda}{a}\) New slit width: \(a' = \frac{a}{2}\)
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