MHT CET · Physics · Waves and Sound
In a resonance tube the first resonance with a tunning fork occurs at \(16 \mathrm{~cm}\) and second at \(49 \mathrm{~cm} .\) If the velocity of sound is \(330 \mathrm{~m} / \mathrm{s}\), the frequency of tunning fork is
- A 500
- B 300
- C 330
- D 165
Answer & Solution
Correct Answer
(A) 500
Step-by-step Solution
Detailed explanation
For closed pipe \(l_{1}=\frac{v}{4 n}\) and \(l_{2}=\frac{3 v}{4 n}\)
\(
\begin{aligned}
v &=2 n\left(l_{2}-l_{1}\right) \\
n &=\frac{v}{2\left(l_{2}-l_{1}\right)} \\
&=\frac{330}{2 \times(0.49-0.16)}=500 \mathrm{~Hz}
\end{aligned}
\)
\(
\begin{aligned}
v &=2 n\left(l_{2}-l_{1}\right) \\
n &=\frac{v}{2\left(l_{2}-l_{1}\right)} \\
&=\frac{330}{2 \times(0.49-0.16)}=500 \mathrm{~Hz}
\end{aligned}
\)
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