MHT CET · Physics · Current Electricity
In a potentiometer experiment, the balancing length for a cell \(240 \mathrm{~cm}\). On shunting the cell with a resistance of \(2 \Omega\), the balancing length become half the initial balancing length. The internal resistance of the cell is
- A \(1.5 \Omega\)
- B \(1 \Omega\)
- C \(0.5 \Omega\)
- D \(2 \Omega\)
Answer & Solution
Correct Answer
(D) \(2 \Omega\)
Step-by-step Solution
Detailed explanation
The internal resistance is given by
\(
\begin{aligned}
& r=R\left(\frac{\ell_1-\ell_2}{\ell_2}\right) \\
& =2\left(\frac{240-120}{120}\right)=2 \Omega
\end{aligned}
\)
\(
\begin{aligned}
& r=R\left(\frac{\ell_1-\ell_2}{\ell_2}\right) \\
& =2\left(\frac{240-120}{120}\right)=2 \Omega
\end{aligned}
\)
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