MHT CET · Physics · Waves and Sound
In a medium, the phase difference between two particles separated by a distance \(x\) is \(\left(\frac{\pi}{5}\right)^{\circ}\). If the frequency of the oscillation of particles is \(25 \mathrm{~Hz}\) and the velocity of propagation of the wave is \(75 \mathrm{~m} / \mathrm{s}\), then the value of \(x\) is
- A \(0.1 \mathrm{~m}\)
- B \(0.2 \mathrm{~m}\)
- C \(0.3 \mathrm{~m}\)
- D \(0.4 \mathrm{~m}\)
Answer & Solution
Correct Answer
(C) \(0.3 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
The wavelength is related to velocity and frequency of the wave by following equation:
The phase difference is given by \(\phi=\frac{2 \pi}{\lambda} x\)
\(\begin{aligned} & \therefore \frac{\pi}{5}=\frac{2 \pi}{3} x \\ & \Rightarrow x=0.3 \mathrm{~m}\end{aligned}\)
The phase difference is given by \(\phi=\frac{2 \pi}{\lambda} x\)
\(\begin{aligned} & \therefore \frac{\pi}{5}=\frac{2 \pi}{3} x \\ & \Rightarrow x=0.3 \mathrm{~m}\end{aligned}\)
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