MHT CET · Physics · Current Electricity
In a given meter bridge, the current flowing through \(40 \Omega\) resistor is
- A \(\mathrm{I}_2+\mathrm{I}_{\mathrm{g}}\)
- B \(\mathrm{I}_{\mathrm{g}}\)
- C \(\mathrm{I}_2-\mathrm{I}_{\mathrm{g}}\)
- D \(\mathrm{I}_2\)
Answer & Solution
Correct Answer
(D) \(\mathrm{I}_2\)
Step-by-step Solution
Detailed explanation
As the bridge is balanced, no current will flow through the galvanometer. Hence, the current through the \(40 \Omega\) resistor will be \(I_2\).
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