MHT CET · Physics · Wave Optics
In a Fraunhoffer diffraction, light of wavelength ' \(\lambda\) ' is incident on slit of width ' \(d\) '. The diffraction pattern is observed on a screen placed at a distance ' D '. The linear width of central maximum is equal to two times the width of the slit, then 'D' has value
- A \(\frac{\mathrm{d}^2}{\lambda}\)
- B \(\frac{\mathrm{d}^2}{2 \lambda}\)
- C \(\frac{\mathrm{d}^2}{3 \lambda}\)
- D \(\frac{\mathrm{d}^2}{4 \lambda}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{d}^2}{\lambda}\)
Step-by-step Solution
Detailed explanation
\(W_{central} = \frac{2 \lambda D}{d}\) \(2d = \frac{2 \lambda D}{d}\)
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