MHT CET · Physics · Semiconductors
In a common emitter transistor amplifier circuit, the input resistance is \(1 \cdot 8 \mathrm{~K} \Omega\) and output is obtained across a load resistance of \(9 \mathrm{~K} \Omega\). The alternating current gain is 70 . Corresponding to an a.c. input voltage of 6 mV , the output voltage will be
- A 0.7 V
- B 1.4 V
- C 2.1 V
- D 4.2 V
Answer & Solution
Correct Answer
(C) 2.1 V
Step-by-step Solution
Detailed explanation
\(A_v = \beta \frac{R_L}{R_{in}}\) \(A_v = 70 \times \frac{9 \mathrm{~K} \Omega}{1.8 \mathrm{~K} \Omega} = 350\)
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