MHT CET · Physics · Wave Optics
In a biprism experiment, the distance of the second dark fringe from the central fringe is 3 mm . The distance of the sixth bright fringe from the central fringe is
- A 12 mm
- B 8 mm
- C 6 mm
- D 4 mm
Answer & Solution
Correct Answer
(A) 12 mm
Step-by-step Solution
Detailed explanation
\( x_2^{dark} = (2 - \frac{1}{2})\frac{\lambda D}{d} = \frac{3}{2}\frac{\lambda D}{d} \) \( \frac{3}{2}\frac{\lambda D}{d} = 3 \text{ mm} \implies \frac{\lambda D}{d} = 2 \text{ mm} \)
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