MHT CET · Physics · Mathematics in Physics
If three vectors have equal magnitude i.e. \(A=B=C\), then the angle between \(\vec{A}\) and
\(\overrightarrow{\mathrm{C}}\) is \(^{\prime} \alpha^{\prime}\). If \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}+\overrightarrow{\mathrm{C}}=0\), then the angle between \(\overrightarrow{\mathrm{A}}\) and \(\overrightarrow{\mathrm{C}}\) is ' \(\beta^{\prime}\), then \(\frac{\alpha}{\beta}\) is
- A \(\frac{2}{3}\)
- B \(\frac{2}{1}\)
- C \(\frac{1}{2}\)
- D \(\frac{3}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(\vec{A}+\vec{B}+\vec{C}=0 \implies \vec{A}+\vec{C}=-\vec{B}\) \(|\vec{A}+\vec{C}|^2 = |-\vec{B}|^2\)
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