MHT CET · Physics · Mechanical Properties of Fluids
If the surface tension of a soap solution is \(3 \times 10^{-2} \mathrm{~N} / \mathrm{m}\), then the work done in
forming a soap film of \(20 \mathrm{~cm} \times 5 \mathrm{~cm}\) will be
- A \(6 \times 10^{-3} \mathrm{~J}\)
- B \(6 \times 10^{-4} \mathrm{~J}\)
- C \(6 \times 10^{-2} \mathrm{~J}\)
- D \(6 \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(6 \times 10^{-4} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
(C)
\(\begin{aligned} W &=2 T \times A \\ &=2 \times 3 \times 10^{-2} \times 100 \times 10^{-4} \\ &=6 \times 10^{-4} \mathrm{~J} \end{aligned}\)
\(\begin{aligned} W &=2 T \times A \\ &=2 \times 3 \times 10^{-2} \times 100 \times 10^{-4} \\ &=6 \times 10^{-4} \mathrm{~J} \end{aligned}\)
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