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MHT CET · Physics · Center of Mass Momentum and Collision

If the radius of the circular path and frequency of revolution of a particle of mass m are doubled, then the change in its kinetic energy will be ( Ei and Ef are the initial and final kinetic energies of the particle respectively,)

  1. A 12 Ef
  2. B 16 Ei
  3. C 8 Ef
  4. D 15 Ei
Verified Solution

Answer & Solution

Correct Answer

(D) 15 Ei

Step-by-step Solution

Detailed explanation

Initial kinetic energy of body,
Ei=12mv2=12m2πr1T1v=2πrT
Ei=2π2mr12f12
Where ,f1 = frequency of revolution of the body.
When, r2=2r1 and f2=2f1 then
Ef=2π2m.r22.f22
=2π2m2r122f12
Ef=32π2mr12f12=16.2π2mr12f12
Ef=16Ei
Change in kinetic energy,
ΔE=Ef-Ei
=16Ei-Ei=15Ei