MHT CET · Physics · Mathematics in Physics
If the maximum percentage error in the measurement of distance (h) and time ( t ) are ' \(e_1\) ' and ' \(e_2\) ' respectively, the percentage error in the measurement of acceleration of gravity ( g ) is [use \(\mathrm{h}=\frac{1}{2} \mathrm{gt}^2\) ]
- A \(e_1+e_2\)
- B \(e_1-2 e_2\)
- C \(e_2-e_1\)
- D \(e_1+2 e_2\)
Answer & Solution
Correct Answer
(D) \(e_1+2 e_2\)
Step-by-step Solution
Detailed explanation
\( \mathrm{h} = \frac{1}{2} \mathrm{gt}^2 \Rightarrow \mathrm{g} = \frac{2\mathrm{h}}{\mathrm{t}^2} \) \( \frac{\Delta \mathrm{g}}{\mathrm{g}} \times 100\% = \left(\frac{\Delta \mathrm{h}}{\mathrm{h}} + 2\frac{\Delta \mathrm{t}}{\mathrm{t}}\right) \times 100\% \)
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