MHT CET · Physics · Oscillations
If the length of the oscillating simple pendulum is made \(\frac{1}{3}\) times the original keeping amplitude same then increase in its total energy at a place will be
- A 3 times
- B 2 times
- C 9 times
- D 5 times
Answer & Solution
Correct Answer
(B) 2 times
Step-by-step Solution
Detailed explanation
\(E = \frac{1}{2} m \omega^2 A^2 = \frac{1}{2} m \frac{g}{L} A^2\) \(E_1 = \frac{1}{2} m \frac{g}{L_1} A^2\)
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