MHT CET · Physics · Dual Nature of Matter
If the kinetic energy of a free electron doubles, its de-Broglie wavelength \(\lambda\) changes by a factor
- A \(2\)
- B \(\frac{1}{\sqrt{2}}\)
- C \(\sqrt{2}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
\(\lambda=\frac{h}{p}=\frac{h}{\sqrt{2(K) m}}\)
Thus, when kinetic energy \(K\) is doubled, the wavelength is changes by a factor of \(\frac{1}{\sqrt{2}}\).
Thus, when kinetic energy \(K\) is doubled, the wavelength is changes by a factor of \(\frac{1}{\sqrt{2}}\).
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