MHT CET · Physics · Capacitance
If the equivalent capacitance between \(\mathrm{A}\) and \(\mathrm{B}\) of the combination of capacitors shown in figure is \(3 \mathrm{C}\), the capacitor \(\mathrm{C}^{\prime}\) 'is equal to

- A 5C
- B 4C
- C 7C
- D 6C
Answer & Solution
Correct Answer
(D) 6C
Step-by-step Solution
Detailed explanation
Consider figure below.

Equivalent capacitance between AP is:
\(\mathrm{C}_{\mathrm{AP}}=3(2 \mathrm{C})\)
As capacitors are connected parallel, the equivalent capacitance of AB is:
\(\frac{1}{\mathrm{C}_{\mathrm{AB}}}=\frac{1}{\mathrm{C}^{\prime}}+\frac{1}{6 \mathrm{C}}=\frac{6 \mathrm{C}+\mathrm{C}^{\prime}}{6 \mathrm{CC}^{\prime}}\)
We know \(\mathrm{C}_{\mathrm{AB}}=3 \mathrm{C}\),
\(\begin{aligned}
& \Rightarrow C_{A B}=\frac{6 C^{\prime}}{6 C+C^{\prime}}=3 C \\
& \Rightarrow 2 C^{\prime}=6 C+C^{\prime} \\
& \Rightarrow C^{\prime}=6 C
\end{aligned}\)

Equivalent capacitance between AP is:
\(\mathrm{C}_{\mathrm{AP}}=3(2 \mathrm{C})\)
As capacitors are connected parallel, the equivalent capacitance of AB is:
\(\frac{1}{\mathrm{C}_{\mathrm{AB}}}=\frac{1}{\mathrm{C}^{\prime}}+\frac{1}{6 \mathrm{C}}=\frac{6 \mathrm{C}+\mathrm{C}^{\prime}}{6 \mathrm{CC}^{\prime}}\)
We know \(\mathrm{C}_{\mathrm{AB}}=3 \mathrm{C}\),
\(\begin{aligned}
& \Rightarrow C_{A B}=\frac{6 C^{\prime}}{6 C+C^{\prime}}=3 C \\
& \Rightarrow 2 C^{\prime}=6 C+C^{\prime} \\
& \Rightarrow C^{\prime}=6 C
\end{aligned}\)
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