MHT CET · Physics · Atomic Physics
If the electron in hydrogen atom jumps from third Bohr orbit to ground state directly and the difference between energies of the two states is radiated in the form of photons. If the work function of the material is \(4 \cdot 1 \mathrm{eV}\), then stopping potential is nearly
\(\left[\text { Energy of electron in } \mathrm{n}^{\text {th }} \text { orbit }=\frac{-13 \cdot 6}{\mathrm{n}^2} \mathrm{eV}\right]\)
- A 3 V
- B 4 V
- C 6 V
- D 8 V
Answer & Solution
Correct Answer
(D) 8 V
Step-by-step Solution
Detailed explanation
\(E_{photon} = E_f - E_i = 13.6 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \mathrm{eV}\) \(E_{photon} = 13.6 \left( \frac{1}{1^2} - \frac{1}{3^2} \right) \mathrm{eV} = 13.6 \left( 1 - \frac{1}{9} \right) \mathrm{eV}\)
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