MHT CET · Physics · Electromagnetic Induction
If the current of ' \(I\) ' gives rise to a magnetic flux ' \(\phi\) ' through a coil having ' \(N\) ' turns, then magnetic energy stored in the medium surrounding the coil is
- A \(\frac{\mathrm{N} \phi \mathrm{I}}{4}\)
- B \(\frac{\mathrm{N} \phi \mathrm{I}}{2}\)
- C \(\frac{\mathrm{NI}}{2 \phi}\)
- D \(\frac{\mathrm{N} \phi}{2 \mathrm{I}}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{N} \phi \mathrm{I}}{2}\)
Step-by-step Solution
Detailed explanation
Inductance of the coil, \(\mathrm{L}=\frac{\phi}{\mathrm{I}}\)
Energy stored due to single turn,
\(
\mathrm{U}=\frac{1}{2} \mathrm{LI}^2=\frac{1}{2}\left(\frac{\phi}{\mathrm{I}}\right) \mathrm{I}^2=\frac{\phi \mathrm{I}}{2}
\)
Energy stored due to \(\mathrm{N}\) turns,
\(
\mathrm{U}^{\prime}=\frac{\mathrm{N} \phi \mathrm{I}}{2}
\)
Energy stored due to single turn,
\(
\mathrm{U}=\frac{1}{2} \mathrm{LI}^2=\frac{1}{2}\left(\frac{\phi}{\mathrm{I}}\right) \mathrm{I}^2=\frac{\phi \mathrm{I}}{2}
\)
Energy stored due to \(\mathrm{N}\) turns,
\(
\mathrm{U}^{\prime}=\frac{\mathrm{N} \phi \mathrm{I}}{2}
\)
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