MHT CET · Physics · Nuclear Physics
If \(\mathrm{T}\) is the half-life of a radioactive substance then its instantaneous rate of change of activity is proportional to
- A \(\sqrt{\mathrm{T}}\)
- B \(\mathrm{T}\)
- C \(\mathrm{T}^{2}\)
- D \(\mathrm{~T}^{-2}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{~T}^{-2}\)
Step-by-step Solution
Detailed explanation
\(\text{Activity, } A = \lambda N\) \(\text{Rate of change of activity, } \frac{dA}{dt} = \lambda \frac{dN}{dt}\)
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