MHT CET · Physics · Kinetic Theory of Gases
If r.m.s. velocity of hydrogen molecules is 4 times that of an oxygen molecule at \(47^{\circ} \mathrm{C}\), the temperature of hydrogen molecules is (Molecular weight of Hydrogen and Oxygen are 2 and 32 respectively)
- A \(23^{\circ} \mathrm{C}\)
- B \(47^{\circ} \mathrm{C}\)
- C \(80^{\circ} \mathrm{C}\)
- D \(114^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(47^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(T_{O_2} = 47^{\circ} \mathrm{C} = 320 \mathrm{K}\) \(\frac{v_{rms, H_2}^2}{v_{rms, O_2}^2} = \frac{T_{H_2}/M_{H_2}}{T_{O_2}/M_{O_2}}\)
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