MHT CET · Physics · Thermodynamics
If \(\mathrm{R}\) is universal gas constant the amount of heat needed to raise the temperature of 2 moles of an ideal monoatomic gas from \(273 \mathrm{~K}\) to \(373 \mathrm{~K}\) when no work is done is
- A \(150 \mathrm{R}\)
- B \(100 \mathrm{R}\)
- C \(500 \mathrm{R}\)
- D \(300 \mathrm{R}\)
Answer & Solution
Correct Answer
(D) \(300 \mathrm{R}\)
Step-by-step Solution
Detailed explanation
For an ideal gas, the internal energy in only a function of the gas temperature and is a measure of the mean translational kinetic energy of the atoms.
\(\Delta \mathrm{Q}=\Delta \mathrm{U}+\Delta \mathrm{Q}=0 \Rightarrow \Delta \mathrm{Q}=\Delta \mathrm{U}=\frac{\mathrm{n}}{2} \mathrm{R} \Delta \mathrm{T}\)
When \(\mathrm{n}=\) degree of freedom for monoatomic gas i.e \(=3\)
\(=\frac{3}{2} \times 2 \mathrm{R}(373-273)=300 \mathrm{R}\)
\(\Delta \mathrm{Q}=\Delta \mathrm{U}+\Delta \mathrm{Q}=0 \Rightarrow \Delta \mathrm{Q}=\Delta \mathrm{U}=\frac{\mathrm{n}}{2} \mathrm{R} \Delta \mathrm{T}\)
When \(\mathrm{n}=\) degree of freedom for monoatomic gas i.e \(=3\)
\(=\frac{3}{2} \times 2 \mathrm{R}(373-273)=300 \mathrm{R}\)
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