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MHT CET · Physics · Atomic Physics

If ' m ' is the mass of electron, ' V ' is its velocity, ' r ' is the radius of stationary circular orbit around a nucleus with charge 'Ze' then from Bohr's first postulate the kinetic energy of the electron is
\(\left(\mathrm{K}=1 / 4 \pi \epsilon_0\right)\)

  1. A \(\frac{\mathrm{Ze}^2}{2 \mathrm{r}} \mathrm{K}\)
  2. B \(\frac{\mathrm{Ze}^2}{2 \mathrm{r}^2} \mathrm{~K}\)
  3. C \(\frac{\mathrm{Ze}^2}{\mathrm{r}} \mathrm{K}\)
  4. D \(\frac{\mathrm{Ze}}{\mathrm{r}^2} \mathrm{~K}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{\mathrm{Ze}^2}{2 \mathrm{r}} \mathrm{K}\)

Step-by-step Solution

Detailed explanation

\(\frac{mV^2}{r} = K \frac{Ze^2}{r^2}\) \(KE = \frac{1}{2}mV^2 = \frac{1}{2} \left( K \frac{Ze^2}{r} \right)\)