MHT CET · Physics · Oscillations
If length of oscillating simple pendulum is made \(\frac{1}{3}\) times at a place keeping amplitude same, then its total energy (E) will be
- A \(6 \mathrm{E}\)
- B \(4 \mathrm{E}\)
- C \(2 \mathrm{E}\)
- D \(3 \mathrm{E}\)
Answer & Solution
Correct Answer
(D) \(3 \mathrm{E}\)
Step-by-step Solution
Detailed explanation
Total energy \(E = \frac{1}{2} m \omega^2 A^2 = \frac{1}{2} m \left(\frac{g}{L}\right) A^2\) Given \(L' = \frac{L}{3}\) and A is constant.
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