MHT CET · Physics · Motion In Two Dimensions
If KE of the particle of mass \(m\) performing UCM in a circle of radius \(r\) is \(E\). Find the acceleration of the particle
- A \(\frac{2 E}{m r}\)
- B \(\left(\frac{2 E}{m r}\right)^{2}\)
- C \(2 \mathrm{Emr}\)
- D \(\frac{4 E}{m r}\)
Answer & Solution
Correct Answer
(A) \(\frac{2 E}{m r}\)
Step-by-step Solution
Detailed explanation
Kinetic energy
\(\frac{1}{2} m v^{2}=E \)
\(\frac{1}{2} m r \frac{v^{2}}{r} =E \)
\(\frac{1}{2} m r a =E \)
\(a =\frac{2 E}{m r}\)
\(\frac{1}{2} m v^{2}=E \)
\(\frac{1}{2} m r \frac{v^{2}}{r} =E \)
\(\frac{1}{2} m r a =E \)
\(a =\frac{2 E}{m r}\)
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