MHT CET · Physics · Ray Optics
If \({ }_{\mathrm{i}} \mu_{\mathrm{j}}\) represents refractive index when ray goes from medium \(\mathrm{i}\) to medium \(\mathrm{j}\), then the product \({ }_2 \mu_1 \mathrm{x}_3 \mu_2 \mathrm{x}_4 \mu_3\) is equal to
- A \(\frac{1}{{ }_3 \mu_2}\)
- B \({ }_3 \mu_2\)
- C \(\frac{1}{{ }_4 \mu_1}\)
- D \({ }_4 \mu_2\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{{ }_4 \mu_1}\)
Step-by-step Solution
Detailed explanation
So, \({ }_2 \mu_1 \times{ }_3 \mu_2 \times{ }_4 \mu_3=\frac{\mu_1}{\mu_2} \times \frac{\mu_2}{\mu_3} \times \frac{\mu_3}{\mu_4}=\frac{\mu_1}{\mu_4}={ }_4 \mu_1\)
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