MHT CET · Physics · Mathematics in Physics
If a unit vector is represented as \(\overrightarrow{\mathrm{u}}=0 \cdot 4 \hat{\imath}+0 \cdot 7 \hat{\jmath}+\mathrm{c} \hat{k}\), then the value of ' \(\mathrm{c}\) ' is
- A \(\sqrt{0 \cdot 11}\)
- B \(\sqrt{0 \cdot 25}\)
- C \(\sqrt{0 \cdot 65}\)
- D \(\sqrt{0 \cdot 35}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{0 \cdot 35}\)
Step-by-step Solution
Detailed explanation
(D)
\(\sqrt{0.4^{2}+0.7^{2}+c^{2}}=1\)
Thus, \(\mathrm{c}^{2}=1-0.65=0.35\), or \(\mathrm{c}=\sqrt{0.35}\)
\(\sqrt{0.4^{2}+0.7^{2}+c^{2}}=1\)
Thus, \(\mathrm{c}^{2}=1-0.65=0.35\), or \(\mathrm{c}=\sqrt{0.35}\)
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