MHT CET · Physics · Alternating Current
If a transformer of an audio amplifier has output impedance \(8000 \Omega\) and the speaker has input impedance \(8 \Omega\), the primary and secondary turns of this transformer connected between the output of amplifier and to loudspeaker should have the ratio
- A \(1000: 1\)
- B \(100: 1\)
- C \(1: 32\)
- D \(32: 1\)
Answer & Solution
Correct Answer
(D) \(32: 1\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \frac{\mathrm{Z}_1}{\mathrm{Z}_2}=\left(\frac{\mathrm{N}_1}{\mathrm{~N}_2}\right)^2 \\ & \frac{8000}{8}=\left(\frac{\mathrm{N}_1}{\mathrm{~N}_2}\right)^2 \\ \therefore \quad & \frac{\mathrm{~N}_1}{\mathrm{~N}_2}=\frac{10 \sqrt{10}}{1} \approx \frac{32}{1}\end{aligned}\)
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