MHT CET · Physics · Magnetic Properties of Matter
If a source emitting waves of frequency \(f\) moves towards an observer with a velocity \(\frac{v}{4}\) and the observer moves away from the source with a velocity \(v / 6\), the apparent frequency as heard by the observer will be \((v=\) velocity of sound)
- A \(\frac{14}{15} f\)
- B \(\frac{14}{9} f\)
- C \(\frac{10}{9} f\)
- D \(\frac{2}{3} f\)
Answer & Solution
Correct Answer
(C) \(\frac{10}{9} f\)
Step-by-step Solution
Detailed explanation
When source and observer both are moving in the same direction and observer is ahead of source, then apparent frequency
\(f^{\prime}=\frac{v-v_{o}}{v-v_{s}} f\)
\(=\frac{v-\frac{v}{6}}{v-\frac{v}{4}}=\frac{\frac{5 v}{6}}{\frac{3 v}{4}} f=\frac{10}{9} f\)
\(f^{\prime}=\frac{v-v_{o}}{v-v_{s}} f\)
\(=\frac{v-\frac{v}{6}}{v-\frac{v}{4}}=\frac{\frac{5 v}{6}}{\frac{3 v}{4}} f=\frac{10}{9} f\)
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