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MHT CET · Physics · Oscillations

If a simple pendulum oscillates with an amplitude of \(50 \mathrm{~mm}\) and time period of \(2 \mathrm{~s}\), then its maximum velocity is

  1. A \(0.10 \mathrm{~ms}^{-1}\)
  2. B \(0.15 \mathrm{~ms}^{-1}\)
  3. C \(0.8 \mathrm{~ms}^{-1}\)
  4. D \(0.26 \mathrm{~ms}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(0.15 \mathrm{~ms}^{-1}\)

Step-by-step Solution

Detailed explanation

\(v_{\max }=a \omega=a \times \frac{2 \pi}{T}=\left(50 \times 10^{-3}\right) \times \frac{2 \pi}{2}\)
\(=0.15 \mathrm{~ms}^{-1}\)
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