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MHT CET · Physics · Atomic Physics

If \(^{\prime} \lambda_{1}\) ' and ' \(\lambda_{2}\) ' are the wavelengths of de-Broglie waves for electrons in first and second Bohr orbits in hydrogen atom, then \(\left(\frac{\lambda_{1}}{\lambda_{2}}\right)\) is equal to (Energy in \(1^{\text {st }}\) Bohr
orbit \(=-13.6 \mathrm{eV}\) )

  1. A \(\frac{1}{5}\)
  2. B \(\frac{1}{2}\)
  3. C \(\frac{1}{4}\)
  4. D \(\frac{1}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

\(\lambda_n = \frac{2\pi r_n}{n}\) \(\lambda_n = \frac{2\pi (n^2 a_0)}{n} = 2\pi n a_0\)