MHT CET · Physics · Thermodynamics
Heat energy is incident on the surface at the rate of \(1000 \mathrm{~J} / \mathrm{min}\). If coefficient of absorption is 0.8 and coefficient of reflection is 0.1 then heat energy transmitted by the surface in 5 minutes is
- A \(100 \mathrm{~J}\)
- B \(500 \mathrm{~J}\)
- C \(700 \mathrm{~J}\)
- D \(900 \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(500 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Let, heat transmitted per minute be \(\mathrm{H}\)
Now,
Energy incident=energy absorbed+energy reflected+energy transmitted
\(\begin{aligned}
& \Rightarrow 1000=0.8 \times 1000+0.1 \times 1000+\mathrm{H} \\
& \Rightarrow \mathrm{H}=100 \mathrm{~J} / \mathrm{min}
\end{aligned}\)
Heat energy transmitted in 5 minutes \(=100 \times 5=500 \mathrm{~J}\)
Now,
Energy incident=energy absorbed+energy reflected+energy transmitted
\(\begin{aligned}
& \Rightarrow 1000=0.8 \times 1000+0.1 \times 1000+\mathrm{H} \\
& \Rightarrow \mathrm{H}=100 \mathrm{~J} / \mathrm{min}
\end{aligned}\)
Heat energy transmitted in 5 minutes \(=100 \times 5=500 \mathrm{~J}\)
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