MHT CET · Physics · Dual Nature of Matter
Graph shows variation of stopping potential with frequency of incident radiation on a metal plate. The value of Planck's constant is [\(\mathrm{e}=\) charge on photoelectron]
- A \(\frac{e\left(V_2-V_1\right)}{v_1 v_2}\)
- B \(\frac{e V_1 V_2}{\left(V_{2-} V_{1}\right)}\)
- C \(\frac{e\left(V_2-V_1\right)}{\left(V_{2-} V_{1}\right)}\)
- D \(\frac{e\left(V_1 V_2\right)}{V_1 V_2}\)
Answer & Solution
Correct Answer
(C) \(\frac{e\left(V_2-V_1\right)}{\left(V_{2-} V_{1}\right)}\)
Step-by-step Solution
Detailed explanation
\(eV = hv - \phi\) \(V = \frac{h}{e}v - \frac{\phi}{e}\)
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