MHT CET · Physics · Thermal Properties of Matter
Given that ' \(x\) ' joule of heat is incident on a body. Out of that, total heat reflected and transmitted is ' \(y\) ' joule. The absorption coefficient of body is-
- A \(\frac{x}{y}\)
- B \(\frac{y}{x}\)
- C \(\frac{x-y}{x}\)
- D \(\frac{y-x}{x}\)
Answer & Solution
Correct Answer
(C) \(\frac{x-y}{x}\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll}
& \mathrm{Q}=\mathrm{x}, \mathrm{Q}_{\mathrm{r}}+\mathrm{Q}_{\mathrm{t}}=\mathrm{y} \\
& \mathrm{Let} \mathrm{L}, \mathrm{Q}=\mathrm{Q}_{\mathrm{a}}+\mathrm{Q}_{\mathrm{r}}+\mathrm{Q}_{\mathrm{t}} \\
\therefore \quad & \mathrm{x}=\mathrm{Q}_{\mathrm{a}}+\mathrm{y} \Rightarrow \mathrm{Q}_{\mathrm{a}}=\mathrm{x}-\mathrm{y}
\end{array}\)
\(\therefore \quad\) Coefficient of absorption, \(a=\frac{Q_a}{Q}=\frac{x-y}{x}\)
& \mathrm{Q}=\mathrm{x}, \mathrm{Q}_{\mathrm{r}}+\mathrm{Q}_{\mathrm{t}}=\mathrm{y} \\
& \mathrm{Let} \mathrm{L}, \mathrm{Q}=\mathrm{Q}_{\mathrm{a}}+\mathrm{Q}_{\mathrm{r}}+\mathrm{Q}_{\mathrm{t}} \\
\therefore \quad & \mathrm{x}=\mathrm{Q}_{\mathrm{a}}+\mathrm{y} \Rightarrow \mathrm{Q}_{\mathrm{a}}=\mathrm{x}-\mathrm{y}
\end{array}\)
\(\therefore \quad\) Coefficient of absorption, \(a=\frac{Q_a}{Q}=\frac{x-y}{x}\)
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