MHT CET · Physics · Rotational Motion
Four thin metal rods each of mass ' \(M\) ' and length ' \(L\) ', are welded end to end to form a square. The moment of inertia of the system about an axis passing through the centre of the square and perpendicular to its plane is
- A \(\frac{\mathrm{ML}^2}{3}\)
- B \(\frac{2 \mathrm{ML}^2}{3}\)
- C \(\frac{2 \mathrm{ML}^2}{9}\)
- D \(\frac{4 \mathrm{ML}^2}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{4 \mathrm{ML}^2}{3}\)
Step-by-step Solution
Detailed explanation

Moment of inertia of the system about an axis passing through O
\(\begin{aligned}
\mathrm{I}_0 & =4\left[\mathrm{MI} \text { of } \operatorname{rod}+\mathrm{m}\left(\frac{\mathrm{~L}}{2}\right)^2\right] \\
& =4\left[\frac{\mathrm{ML}^2}{12}+\frac{\mathrm{ML}^2}{4}\right] \\
& =\frac{4}{3} \mathrm{ML}^2
\end{aligned}\)
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