MHT CET · Physics · Rotational Motion
Four particles each of mass M are placed at the corners of a square of side L . The radius of gyration of the system about an axis perpendicular to the square and passing through its centre is
- A L
- B \(\frac{L}{2}\)
- C \(\frac{L}{4}\)
- D \(\frac{\mathrm{L}}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{L}}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
\(I = \sum mr^2\) \(r = \frac{1}{2}\sqrt{L^2+L^2} = \frac{L}{\sqrt{2}}\)
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