MHT CET · Physics · Kinetic Theory of Gases
Four moles of hydrogen, two moles of helium and one mole of water vapour form an ideal gas mixture. \(\left[C_v\right.\) for hydrogen \(=\frac{5}{2} R, \quad C_v\) for helium \(=\frac{3}{2} R, \quad C_v \quad\) for water vapour \(\left.=3 R\right]\) What is the molar specific heat at constant pressure of the mixture?
- A \(\frac{11}{3} \mathrm{R}\)
- B \(\frac{23}{7} \mathrm{R}\)
- C \(\frac{16}{7} \mathrm{R}\)
- D \(\frac{23}{3} \mathrm{R}\)
Answer & Solution
Correct Answer
(B) \(\frac{23}{7} \mathrm{R}\)
Step-by-step Solution
Detailed explanation
\(C_p=C_v+R\)
\(\therefore \quad \mathrm{C}_{\mathrm{p}}\) for hydrogen, \(\mathrm{C}_{\mathrm{p}_1}=\frac{7}{2} \mathrm{R}\)
\(\mathrm{C}_{\mathrm{p}}\) for helium, \(\mathrm{C}_{\mathrm{p}_2}=\frac{5}{2} \mathrm{R}\)
\(\mathrm{C}_{\mathrm{p}}\) for water vapour, \(\mathrm{C}_{\mathrm{p}_3}=4 \mathrm{R}\)
Also, \(\mathrm{n}_1=4, \mathrm{n}_2=2\) and \(\mathrm{n}_3=1\)
\(\begin{aligned}
C_p \text { of mixture } & =\frac{n_1 C_{p_1}+n_2 C_{p_2}+n_3 C_{p_3}}{n_1+n_2+n_3} \\
& =\frac{4 \times \frac{7 R}{2}+2 \times \frac{5 R}{2}+4 R}{4+2+1} \\
& =\frac{14 R+5 R+4 R}{7}=\frac{23 R}{7}
\end{aligned}\)
\(\therefore \quad \mathrm{C}_{\mathrm{p}}\) for hydrogen, \(\mathrm{C}_{\mathrm{p}_1}=\frac{7}{2} \mathrm{R}\)
\(\mathrm{C}_{\mathrm{p}}\) for helium, \(\mathrm{C}_{\mathrm{p}_2}=\frac{5}{2} \mathrm{R}\)
\(\mathrm{C}_{\mathrm{p}}\) for water vapour, \(\mathrm{C}_{\mathrm{p}_3}=4 \mathrm{R}\)
Also, \(\mathrm{n}_1=4, \mathrm{n}_2=2\) and \(\mathrm{n}_3=1\)
\(\begin{aligned}
C_p \text { of mixture } & =\frac{n_1 C_{p_1}+n_2 C_{p_2}+n_3 C_{p_3}}{n_1+n_2+n_3} \\
& =\frac{4 \times \frac{7 R}{2}+2 \times \frac{5 R}{2}+4 R}{4+2+1} \\
& =\frac{14 R+5 R+4 R}{7}=\frac{23 R}{7}
\end{aligned}\)
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