MHT CET · Physics · Laws of Motion
Four massless springs whose force constants are \(2 \mathrm{~K}, 2 \mathrm{~K}, \mathrm{~K}\) and \(2 \mathrm{~K}\) respectively are attached to a mass \(\mathrm{M}\) kept on a frictionless plane as shown in figure, If mass \(M\) is displaced in horizontal direction then frequency of oscillating system is

- A \(\frac{1}{2 \pi} \sqrt{\frac{\mathrm{K}}{4 \mathrm{M}}}\)
- B \(\frac{1}{2 \pi} \sqrt{\frac{4 \mathrm{~K}}{\mathrm{M}}}\)
- C \(\frac{1}{2 \pi} \sqrt{\frac{\mathrm{K}}{7 \mathrm{M}}}\)
- D \(\frac{1}{2 \pi} \sqrt{\frac{7 \mathrm{~K}}{\mathrm{M}}}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2 \pi} \sqrt{\frac{4 \mathrm{~K}}{\mathrm{M}}}\)
Step-by-step Solution
Detailed explanation
On the right hand side of the block, springs are connected in parallel
\(\therefore\) Their effective spring constant is given by
\(
\begin{aligned}
& \mathrm{K}_1=\mathrm{K}+2 \mathrm{~K} \\
& \mathrm{~K}_1=3 \mathrm{~K}
\end{aligned}
\)
On the left hand side of the block, springs are connected in series.
\(\therefore\) Their effective spring constant is given by,
\(\frac{1}{\mathrm{~K}_2}=\frac{1}{2 \mathrm{~K}}+\frac{1}{2 \mathrm{~K}} \)
\( \therefore \quad \mathrm{K}_2 =\mathrm{K}\)
\(\therefore\) Effective spring constant of the system is given by,
\(\mathrm{K}_{\mathrm{E}}=3 \mathrm{~K}+\mathrm{K}=4 \mathrm{~K} \)
\( \therefore \omega =\sqrt{\frac{\mathrm{K}_{\mathrm{E}}}{\mathrm{M}}}=\sqrt{\frac{4 \mathrm{~K}}{\mathrm{M}}} \)
\( \therefore \mathrm{f} =\frac{\omega}{2 \pi}=\frac{1}{2 \pi} \sqrt{\frac{4 \mathrm{~K}}{\mathrm{M}}}\)
\(\therefore\) Their effective spring constant is given by
\(
\begin{aligned}
& \mathrm{K}_1=\mathrm{K}+2 \mathrm{~K} \\
& \mathrm{~K}_1=3 \mathrm{~K}
\end{aligned}
\)
On the left hand side of the block, springs are connected in series.
\(\therefore\) Their effective spring constant is given by,
\(\frac{1}{\mathrm{~K}_2}=\frac{1}{2 \mathrm{~K}}+\frac{1}{2 \mathrm{~K}} \)
\( \therefore \quad \mathrm{K}_2 =\mathrm{K}\)
\(\therefore\) Effective spring constant of the system is given by,
\(\mathrm{K}_{\mathrm{E}}=3 \mathrm{~K}+\mathrm{K}=4 \mathrm{~K} \)
\( \therefore \omega =\sqrt{\frac{\mathrm{K}_{\mathrm{E}}}{\mathrm{M}}}=\sqrt{\frac{4 \mathrm{~K}}{\mathrm{M}}} \)
\( \therefore \mathrm{f} =\frac{\omega}{2 \pi}=\frac{1}{2 \pi} \sqrt{\frac{4 \mathrm{~K}}{\mathrm{M}}}\)
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