MHT CET · Physics · Waves and Sound
For the stationary wave
\(
y=4 \sin \left(\frac{\pi x}{15}\right) \cos (96 \pi t)
\)
the distance between a node and the next antinode is
- A \(7.5\)
- B 15
- C \(22.5\)
- D 30
Answer & Solution
Correct Answer
(A) \(7.5\)
Step-by-step Solution
Detailed explanation
On comparing given equation with standard equation, we get
\(
\Rightarrow \quad \begin{array}{l}
\frac{2 \pi}{\lambda}=\frac{\pi}{15} \\
\Rightarrow \quad \lambda=30
\end{array}
\)
Distance between the node and antinode
\(
=\frac{\lambda}{4}
\)
\(
=\frac{30}{4}=7.5
\)
\(
\Rightarrow \quad \begin{array}{l}
\frac{2 \pi}{\lambda}=\frac{\pi}{15} \\
\Rightarrow \quad \lambda=30
\end{array}
\)
Distance between the node and antinode
\(
=\frac{\lambda}{4}
\)
\(
=\frac{30}{4}=7.5
\)
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