MHT CET · Physics · Semiconductors
For the following combination of logic gates, when all the three inputs \(A\), \(B\) and \(C\) are first 'high' and then 'low', the output \(Y\) will be respectively.
- A 0,0
- B 0,1
- C 1,0
- D 1,1
Answer & Solution
Correct Answer
(B) 0,1
Step-by-step Solution
Detailed explanation
Let inputs \(A, B\) and \(C\) are given to the circuit.
Gate-I is AND gate while gate-II is NAND gate.
Output \(Y=\overline{(A . B . C)}\)
When \(A=1, B=1, C=1\), then
\(Y=\overline{(1 \cdot 1) \cdot 1}=\overline{1 \cdot 1}=\overline{1}=0\)
When \(A=0, B=0, C=0\), then
\(Y=\overline{(0.0) \cdot 0}=\overline{0.0}=1\)
Gate-I is AND gate while gate-II is NAND gate.
Output \(Y=\overline{(A . B . C)}\)
When \(A=1, B=1, C=1\), then
\(Y=\overline{(1 \cdot 1) \cdot 1}=\overline{1 \cdot 1}=\overline{1}=0\)
When \(A=0, B=0, C=0\), then
\(Y=\overline{(0.0) \cdot 0}=\overline{0.0}=1\)
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