MHT CET · Physics · Kinetic Theory of Gases
For polyatomic gases, the ratio of molar specific heat at constant pressure to constant volume is \((\mathrm{f}=\) degrees of freedom \()\)
- A \(\frac{2+\mathrm{f}}{3+\mathrm{f}}\)
- B \(\frac{3+\mathrm{f}}{2+\mathrm{f}}\)
- C \(\frac{3+\mathrm{f}}{4+\mathrm{f}}\)
- D \(\frac{4+f}{3+f}\)
Answer & Solution
Correct Answer
(D) \(\frac{4+f}{3+f}\)
Step-by-step Solution
Detailed explanation
For polyatomic gases, molar-specific heat at constant volume is \(\mathrm{C}_{\mathrm{V}}=(3+\mathrm{f}) \mathrm{R}\) and Molar-specific heat at constant pressure is \(\mathrm{C}_{\mathrm{P}}=(4+\mathrm{f}) \mathrm{R}\)
\(\therefore \quad \frac{\mathrm{C}_{\mathrm{P}}}{\mathrm{C}_{\mathrm{V}}}=\frac{4+\mathrm{f}}{3+\mathrm{f}}\)
\(\therefore \quad \frac{\mathrm{C}_{\mathrm{P}}}{\mathrm{C}_{\mathrm{V}}}=\frac{4+\mathrm{f}}{3+\mathrm{f}}\)
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