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MHT CET · Physics · Atomic Physics

For hydrogen atom, ' \(\lambda_1\) ' and ' \(\lambda_2\) ' are the wavelengths corresponding to the transitions 1 and 2 respectively as shown in figure. The ratio of ' \(\lambda_1\) ' and ' \(\lambda_2\) ' is \(\frac{x}{32}\). The value of ' \(x\) ' is

  1. A 3
  2. B 9
  3. C 27
  4. D 81
Verified Solution

Answer & Solution

Correct Answer

(C) 27

Step-by-step Solution

Detailed explanation

\(\frac{1}{\lambda_1}=\mathrm{R}\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right]=\mathrm{R}\left[\frac{1}{1^2}-\frac{1}{3^2}\right]=\frac{8}{9} \mathrm{R}\)
Similarly; \(\frac{1}{\lambda_2}=R\left[\frac{1}{1^2}-\frac{1}{2^2}\right]=\frac{3}{4} R\)
\(\begin{aligned}
& \therefore \quad \frac{\frac{1}{\lambda_1}}{\frac{1}{\lambda_2}}=\frac{\frac{8}{9} \mathrm{R}}{\frac{3}{4} R} \\
& \therefore \quad \frac{\lambda_1}{\lambda_2}=\frac{27}{32} \\
& \therefore \quad x=27
\end{aligned}\)