MHT CET · Physics · Semiconductors
For a transistor, \(\alpha_{\mathrm{dc}}\) and \(\beta_{\mathrm{dc}}\) are the current ratios, then the value of \(\frac{\beta_{\mathrm{dc}}-\alpha_{\mathrm{dc}}}{\alpha_{\mathrm{dc}} \times \beta_{\mathrm{dc}}}\)
- A 2.5
- B 2
- C 1.5
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
\( \beta_{\mathrm{dc}} = \frac{\alpha_{\mathrm{dc}}}{1 - \alpha_{\mathrm{dc}}} \implies \frac{1}{\beta_{\mathrm{dc}}} = \frac{1 - \alpha_{\mathrm{dc}}}{\alpha_{\mathrm{dc}}} \) \( \frac{\beta_{\mathrm{dc}}-\alpha_{\mathrm{dc}}}{\alpha_{\mathrm{dc}} \times \beta_{\mathrm{dc}}} = \frac{1}{\alpha_{\mathrm{dc}}} - \frac{1}{\beta_{\mathrm{dc}}} \)
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