MHT CET · Physics · Semiconductors
For a transistor, current gain \((\beta)=50\). To change the collector current by \(350 \mu \mathrm{~A}\), the base current should be changed by
- A \(\left(\frac{50}{350}\right) . \mu \mathrm{A}\)
- B \((350-50) \mu \mathrm{A}\)
- C \((350+50) \mu \mathrm{A}\)
- D \(\left(\frac{350}{50}\right) \mu \mathrm{A}\)
Answer & Solution
Correct Answer
(D) \(\left(\frac{350}{50}\right) \mu \mathrm{A}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \beta=\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}} \\ \therefore \quad & \Delta \mathrm{I}_{\mathrm{B}}=\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\dot{\beta}}=\frac{350}{50} \mu \mathrm{~A}\end{aligned}\)
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