MHT CET · Physics · Semiconductors
For a transistor, \(\frac{1}{\alpha_{D C}}-\frac{1}{\beta_{D C}}\) is equal to \(\left[\alpha_{D C}\right.\) and \(\beta_{D C}\) are current amplification factors]
- A three
- B two
- C zero
- D one
Answer & Solution
Correct Answer
(D) one
Step-by-step Solution
Detailed explanation
\(
\begin{aligned}
&\frac{1}{\alpha_{D C}}-\frac{1}{\beta_{D C}}=\frac{I_e}{I_c}-\frac{I_b}{I_c}\\
&\frac{I_e-I_b}{I_c}=\frac{I_c}{I_c}=1
\end{aligned}
\)
\begin{aligned}
&\frac{1}{\alpha_{D C}}-\frac{1}{\beta_{D C}}=\frac{I_e}{I_c}-\frac{I_b}{I_c}\\
&\frac{I_e-I_b}{I_c}=\frac{I_c}{I_c}=1
\end{aligned}
\)
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