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MHT CET · Physics · Semiconductors

For a transistor, \(\frac{1}{\alpha_{D C}}-\frac{1}{\beta_{D C}}\) is equal to \(\left[\alpha_{D C}\right.\) and \(\beta_{D C}\) are current amplification factors]

  1. A three
  2. B two
  3. C zero
  4. D one
Verified Solution

Answer & Solution

Correct Answer

(D) one

Step-by-step Solution

Detailed explanation

\(
\begin{aligned}
&\frac{1}{\alpha_{D C}}-\frac{1}{\beta_{D C}}=\frac{I_e}{I_c}-\frac{I_b}{I_c}\\
&\frac{I_e-I_b}{I_c}=\frac{I_c}{I_c}=1
\end{aligned}
\)