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MHT CET · Physics · Ray Optics

For a thin prism, \(\delta_1\) is the angle of deviation produced, when prism is placed in air. When the prism is immersed in water, the angle of deviation produced is \(\delta_2\). Given \({ }_{\mathrm{a}} \mu_{\mathrm{g}}=\frac{3}{2}\) and \({ }_{\mathrm{a}} \mu_{\mathrm{w}}=\frac{4}{3}\). The ratio \(\delta_2: \delta_1\) is

  1. A \(1: 2\)
  2. B \(1: 4\)
  3. C \(1: 8\)
  4. D \(4: 1\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1: 4\)

Step-by-step Solution

Detailed explanation

\(\delta_1 = A({ }_{\mathrm{a}} \mu_{\mathrm{g}} - 1) = A\left(\frac{3}{2} - 1\right) = A\left(\frac{1}{2}\right)\) \({ }_{\mathrm{w}} \mu_{\mathrm{g}} = \frac{{ }_{\mathrm{a}} \mu_{\mathrm{g}}}{{ }_{\mathrm{a}} \mu_{\mathrm{w}}} = \frac{3/2}{4/3} = \frac{9}{8}\)