MHT CET · Physics · Ray Optics
For a thin prism, \(\delta_1\) is the angle of deviation produced, when prism is placed in air. When the prism is immersed in water, the angle of deviation produced is \(\delta_2\). Given \({ }_{\mathrm{a}} \mu_{\mathrm{g}}=\frac{3}{2}\) and \({ }_{\mathrm{a}} \mu_{\mathrm{w}}=\frac{4}{3}\). The ratio \(\delta_2: \delta_1\) is
- A \(1: 2\)
- B \(1: 4\)
- C \(1: 8\)
- D \(4: 1\)
Answer & Solution
Correct Answer
(B) \(1: 4\)
Step-by-step Solution
Detailed explanation
\(\delta_1 = A({ }_{\mathrm{a}} \mu_{\mathrm{g}} - 1) = A\left(\frac{3}{2} - 1\right) = A\left(\frac{1}{2}\right)\) \({ }_{\mathrm{w}} \mu_{\mathrm{g}} = \frac{{ }_{\mathrm{a}} \mu_{\mathrm{g}}}{{ }_{\mathrm{a}} \mu_{\mathrm{w}}} = \frac{3/2}{4/3} = \frac{9}{8}\)
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