MHT CET · Physics · Ray Optics
For a symmetric (equilateral) prism, the prism formula can be written as
- A \(2 \sin \left(30+\frac{\delta m}{2}\right)\)
- B \(\frac{2}{\sqrt{3}} \sin \left(30+\frac{\delta \mathrm{m}}{2}\right)\)
- C \(2 \sin \left(60+\frac{\delta \mathrm{m}}{2}\right)\)
- D \(\frac{2}{\sqrt{3}} \sin \left(60+\frac{\delta \mathrm{m}}{2}\right)\)
Answer & Solution
Correct Answer
(A) \(2 \sin \left(30+\frac{\delta m}{2}\right)\)
Step-by-step Solution
Detailed explanation
\(\mu=\frac{\sin \left(\frac{A+\delta m}{2}\right)}{\sin \left(\frac{A}{2}\right)}\)
For symmetric prism, \(\mathrm{A}=60^{\circ}\)
\(\therefore \mu =\frac{\sin \left(30+\frac{\delta \mathrm{m}}{2}\right)}{\sin 30}\)
\(=2 \sin \left(30+\frac{\delta \mathrm{m}}{2}\right) \quad \ldots\left(\because \sin 30^{\circ}=\frac{1}{2}\right)\)
For symmetric prism, \(\mathrm{A}=60^{\circ}\)
\(\therefore \mu =\frac{\sin \left(30+\frac{\delta \mathrm{m}}{2}\right)}{\sin 30}\)
\(=2 \sin \left(30+\frac{\delta \mathrm{m}}{2}\right) \quad \ldots\left(\because \sin 30^{\circ}=\frac{1}{2}\right)\)
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