MHT CET · Physics · Oscillations
For a particle performing linear S.H.M., its average speed over one oscillation is
( \(A=\) amplitude of S.H.M., \(n=\) frequency of oscillation)
- A 4nA
- B 8nA
- C 2nA
- D 6nA
Answer & Solution
Correct Answer
(A) 4nA
Step-by-step Solution
Detailed explanation
Distance covered per oscillation, \(s=4 a\)
Time taken for one oscillation, \(T=\frac{1}{n}\)
Hence, the average speed per oscillation \(v_{a v}=\frac{S}{T}=4 a n\)
Time taken for one oscillation, \(T=\frac{1}{n}\)
Hence, the average speed per oscillation \(v_{a v}=\frac{S}{T}=4 a n\)
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